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when is greg abbott term over - Belip

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 This means \(n^3 \equiv 888 \pmod{8}\) and \(n^3 \equiv 888 \pmod{125}\), since \(1000 = 8 imes 125\) and \(\gcd(8,125)=1\).

📌 Step 1: Solve modulo 8

📌 \(888 \equiv 0 \pmod{8}\), so:

📌 n^3 \equiv 0 \pmod{8} \Rightarrow n \equiv 0 \pmod{2}

📌 In fact, since \(8 = 2^3\), for \(n^3 \equiv 0 \pmod{8}\), \(n\) must be divisible by 2. Try small even values:

📌 If \(n \equiv 0 \pmod{2}\), then \(n^3 \equiv 0 \pmod{8}\) only if \(n \equiv 0, 2, 4, 6 \pmod{8}\), but:

📌 \(2^3 = 8 \equiv 0\)

📌 \(4^3 = 64 \equiv 0\)

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