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📰 ight) - 2 \geq 2 - 2 = 0, 📰 with equality only if $ rac{p+q}{p-q} = rac{p-q}{p+q} $, which implies $ (p+q)^2 = (p-q)^2 \Rightarrow 4pq = 0 $, impossible. So $ R > 0 $, but infimum is 0. But the problem asks for minimum. However, since $ p > q > 0 $, $ R > 0 $, but can be arbitrarily small. Thus, no minimum? But wait — perhaps we misread. Let’s compute minimum numerically. Let $ x = rac{p}{q} > 1 $, so 📰 R = rac{x + 1}{x - 1} + rac{x - 1}{x + 1} - 2. 📰 Gendo Ikaris Shocking Motives Revealedyou Wont Believe His Hidden Agenda 1358379 📰 Free Mah Jong 9102149 📰 United Healthcare Careers Work From Home 6821986 📰 Public Health Public How This Movement Is Changing Global Wellness Forever 6619956 📰 Tahu Roblox Game 196314 📰 Currency Usd To Ruble 1857456 📰 Unlock Hidden Data Excel Text To Columns Secrets Youll Cant Ignore 8660310 📰 Lid The Shocking Truth Behind The Ordinary Trigger 4617250 📰 Braves Vs Mets 9811930 📰 Art Of Thinking Clearly 6758488 📰 Stop Wasting Money Flex Spending Vs Hsa Comparison You Must See Before Its Too Late 6356650 📰 Secured Big Gainsibg Ticker Just Hit A Historic High Unlock Your Share Now 7814188 📰 Ein Biomedizinischer Ingenieur Modelliert Die Spannungskonzentration S An Einem Implantat Als S Frac2 Gammapi A Wobei Gamma 50 Mpa Und A Der Rissradius In Mm Ist Wenn Die Maximal Zulssige Spannung 20 Mpa Betrgt Wie Gro Ist Der Maximale Zulssige Rissradius 2885787 📰 Which Branch Enforces Laws 2799052 📰 Car Building Simulator 4384410