A solution is made by mixing 3 liters of a 25% acid solution with a 50% acid solution to get a 40% acid solution. How many liters of the 50% solution must be added?

Sun, 03 May 2026 00:13:31 +0000

**A solution is made by mixing 3 liters of a 25% acid solution with a 50% acid solution to get a 40% acid solution. How many liters of the 50% solution must be added?** This practical chemistry question is gaining quiet attention across US science and DIY communities—driven by a growing interest in basic acid-base mixing, household chemistry, and informed decision-making. Many are exploring how precise dilution affects concentration in everyday solutions, whether for educational purposes, household projects, or understanding industrial processes. The scenario—combining a known source with a stronger acid to reach a target concentration—lies at the core of dilution science, with applications far beyond the lab. **Why A solution is made by mixing 3 liters of a 25% acid solution with a 50% acid solution to get a 40% acid solution. How many liters of the 50% solution must be added?**
This question reflects real-world curiosity about accurate mixing ratios driven by both safety and practical outcome. Whether in educational settings, hobby labs, or industrial mixing, precise concentration predicts effectiveness and risk. Mixing solutions applies to many areas—cleaning, personal care formulations, or pharmaceuticals—where small changes in acid levels matter significantly. **How A solution is made by mixing 3 liters of a 25% acid solution with a 50% acid solution to get a 40% acid solution. How many liters of the 50% solution must be added?**
Actual calculations reveal a straightforward but precise method. Let $ x $ be the liters of 50% solution to add. Starting with 3 liters of 25% acid, adding $ x $ liters of 50% acid gives a total volume of $ 3 + x $ liters. Total acid content is $ 0.25(3) + 0.50x $. To reach 40% concentration, set up the equation: