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desmoplastic small round cell tumor - Belip

📅 May 6, 2026 👤 scraface

May 06, 2026

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Therefore, the signal reaches **2 points**.
Wait — contradiction.
Let’s re-solve the system:
\frac{x^2}{100} + \frac{y^2}{64} = 1 \quad \text{(ellipse)}
x^2 + y^2 = 64 \quad \text{(circle)}
From second, \( y^2 = 64 - x^2 \). Substitute:
x^2 \left( \frac{64 - 100}{6400} \right) = 0 \Rightarrow x^2 \cdot (-3...
So \( x^2 = 0 \), hence \( x = 0 \), \( y = \pm8 \).
Only **two** solutions.
Therefore, the signal reaches exactly **2 points** on the orbit.

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